13232200340041 has 4 divisors (see below), whose sum is σ = 13240363327684. Its totient is φ = 13224037352400.

The previous prime is 13232200340039. The next prime is 13232200340057. The reversal of 13232200340041 is 14004300223231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9325663902025 + 3906536438016 = 3053795^2 + 1976496^2 .

It is a cyclic number.

It is not a de Polignac number, because 13232200340041 - 2¹ = 13232200340039 is a prime.

It is a super-2 number, since 2×13232200340041² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13232200339988 and 13232200340015.

It is not an unprimeable number, because it can be changed into a prime (13232200346041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4081491390 + ... + 4081494631.

It is an arithmetic number, because the mean of its divisors is an integer number (3310090831921).

Almost surely, 2^{13232200340041} is an apocalyptic number.

It is an amenable number.

13232200340041 is a deficient number, since it is larger than the sum of its proper divisors (8162987643).

13232200340041 is an equidigital number, since it uses as much as digits as its factorization.

13232200340041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8162987642.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 13232200340041 its reverse (14004300223231), we get a palindrome (27236500563272).

The spelling of 13232200340041 in words is "thirteen trillion, two hundred thirty-two billion, two hundred million, three hundred forty thousand, forty-one".