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13232203203481 is a prime number
BaseRepresentation
bin1100000010001101110011…
…0001011000001110011001
31201211222121222210110010221
43000203130301120032121
53213244023010002411
644050442405040041
72533665221305123
oct300433461301631
951758558713127
1013232203203481
114241822822349
1215985a60b6021
1374ca39953182
1433a628dc4213
1517e2eed86071
hexc08dcc58399

13232203203481 has 2 divisors, whose sum is σ = 13232203203482. Its totient is φ = 13232203203480.

The previous prime is 13232203203473. The next prime is 13232203203551. The reversal of 13232203203481 is 18430230223231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13083123043600 + 149080159881 = 3617060^2 + 386109^2 .

It is a cyclic number.

It is not a de Polignac number, because 13232203203481 - 23 = 13232203203473 is a prime.

It is a super-2 number, since 2×132322032034812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13232203203281) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6616101601740 + 6616101601741.

It is an arithmetic number, because the mean of its divisors is an integer number (6616101601741).

Almost surely, 213232203203481 is an apocalyptic number.

It is an amenable number.

13232203203481 is a deficient number, since it is larger than the sum of its proper divisors (1).

13232203203481 is an equidigital number, since it uses as much as digits as its factorization.

13232203203481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 34.

The spelling of 13232203203481 in words is "thirteen trillion, two hundred thirty-two billion, two hundred three million, two hundred three thousand, four hundred eighty-one".