Base | Representation |
---|---|
bin | 10011010000010110000… |
… | …101110100110111110001 |
3 | 11200111110111220202221002 |
4 | 103100112011310313301 |
5 | 133134423430200301 |
6 | 2451513520411345 |
7 | 164412432060251 |
oct | 23202605646761 |
9 | 4614414822832 |
10 | 1323220553201 |
11 | 4701a1562528 |
12 | 194547a76b55 |
13 | 97a18a88a51 |
14 | 48089489961 |
15 | 2464779e16b |
hex | 13416174df1 |
1323220553201 has 2 divisors, whose sum is σ = 1323220553202. Its totient is φ = 1323220553200.
The previous prime is 1323220553191. The next prime is 1323220553243. The reversal of 1323220553201 is 1023550223231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1206649522576 + 116571030625 = 1098476^2 + 341425^2 .
It is a cyclic number.
It is not a de Polignac number, because 1323220553201 - 238 = 1048342646257 is a prime.
It is not a weakly prime, because it can be changed into another prime (1323220553401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661610276600 + 661610276601.
It is an arithmetic number, because the mean of its divisors is an integer number (661610276601).
Almost surely, 21323220553201 is an apocalyptic number.
It is an amenable number.
1323220553201 is a deficient number, since it is larger than the sum of its proper divisors (1).
1323220553201 is an equidigital number, since it uses as much as digits as its factorization.
1323220553201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 29.
Adding to 1323220553201 its reverse (1023550223231), we get a palindrome (2346770776432).
The spelling of 1323220553201 in words is "one trillion, three hundred twenty-three billion, two hundred twenty million, five hundred fifty-three thousand, two hundred one".
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