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1323222113531 is a prime number
BaseRepresentation
bin10011010000010110001…
…011110001110011111011
311200111110121212001022002
4103100112023301303323
5133134424330113111
62451514014051215
7164412451246313
oct23202613616373
94614417761262
101323222113531
114701a242885a
121945484a9b0b
1397a191b4016
1448089774443
15246479ab63b
hex134162f1cfb

1323222113531 has 2 divisors, whose sum is σ = 1323222113532. Its totient is φ = 1323222113530.

The previous prime is 1323222113459. The next prime is 1323222113539. The reversal of 1323222113531 is 1353112223231.

It is a strong prime.

It is an emirp because it is prime and its reverse (1353112223231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1323222113531 - 230 = 1322148371707 is a prime.

It is a super-2 number, since 2×13232221135312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1323222113494 and 1323222113503.

It is not a weakly prime, because it can be changed into another prime (1323222113539) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661611056765 + 661611056766.

It is an arithmetic number, because the mean of its divisors is an integer number (661611056766).

Almost surely, 21323222113531 is an apocalyptic number.

1323222113531 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323222113531 is an equidigital number, since it uses as much as digits as its factorization.

1323222113531 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6480, while the sum is 29.

Adding to 1323222113531 its reverse (1353112223231), we get a palindrome (2676334336762).

The spelling of 1323222113531 in words is "one trillion, three hundred twenty-three billion, two hundred twenty-two million, one hundred thirteen thousand, five hundred thirty-one".