Base | Representation |
---|---|
bin | 111101100111100010… |
… | …1011101010000101001 |
3 | 110122112211200210120011 |
4 | 1323033011131100221 |
5 | 4131444233130121 |
6 | 140442152131521 |
7 | 12363044526265 |
oct | 1731705352051 |
9 | 418484623504 |
10 | 132323333161 |
11 | 51133087788 |
12 | 2178a996ba1 |
13 | c62a329296 |
14 | 6593c8d0a5 |
15 | 3696ce37e1 |
hex | 1ecf15d429 |
132323333161 has 2 divisors, whose sum is σ = 132323333162. Its totient is φ = 132323333160.
The previous prime is 132323333123. The next prime is 132323333239. The reversal of 132323333161 is 161333323231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 89030624400 + 43292708761 = 298380^2 + 208069^2 .
It is an emirp because it is prime and its reverse (161333323231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132323333161 - 211 = 132323331113 is a prime.
It is not a weakly prime, because it can be changed into another prime (132323337161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66161666580 + 66161666581.
It is an arithmetic number, because the mean of its divisors is an integer number (66161666581).
Almost surely, 2132323333161 is an apocalyptic number.
It is an amenable number.
132323333161 is a deficient number, since it is larger than the sum of its proper divisors (1).
132323333161 is an equidigital number, since it uses as much as digits as its factorization.
132323333161 is an evil number, because the sum of its binary digits is even.
The product of its digits is 17496, while the sum is 31.
Adding to 132323333161 its reverse (161333323231), we get a palindrome (293656656392).
The spelling of 132323333161 in words is "one hundred thirty-two billion, three hundred twenty-three million, three hundred thirty-three thousand, one hundred sixty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •