Base | Representation |
---|---|
bin | 111101100111100100… |
… | …0000110001100111011 |
3 | 110122112212222221210021 |
4 | 1323033020012030323 |
5 | 4131444422301042 |
6 | 140442215031311 |
7 | 12363053440606 |
oct | 1731710061473 |
9 | 418485887707 |
10 | 132324025147 |
11 | 5113350a676 |
12 | 2178b06b537 |
13 | c62a50c242 |
14 | 6593dcd33d |
15 | 3696dcd867 |
hex | 1ecf20633b |
132324025147 has 2 divisors, whose sum is σ = 132324025148. Its totient is φ = 132324025146.
The previous prime is 132324025117. The next prime is 132324025153. The reversal of 132324025147 is 741520423231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132324025147 - 215 = 132323992379 is a prime.
It is a super-2 number, since 2×1323240251472 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132324025117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66162012573 + 66162012574.
It is an arithmetic number, because the mean of its divisors is an integer number (66162012574).
Almost surely, 2132324025147 is an apocalyptic number.
132324025147 is a deficient number, since it is larger than the sum of its proper divisors (1).
132324025147 is an equidigital number, since it uses as much as digits as its factorization.
132324025147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40320, while the sum is 34.
Adding to 132324025147 its reverse (741520423231), we get a palindrome (873844448378).
The spelling of 132324025147 in words is "one hundred thirty-two billion, three hundred twenty-four million, twenty-five thousand, one hundred forty-seven".
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