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13232444144041 = 108943121462087
BaseRepresentation
bin1100000010001110101100…
…1000011111100110101001
31201212000020210011111110101
43000203223020133212221
53213300021200102131
644050522333145401
72534004205255543
oct300435310374651
951760223144411
1013232444144041
114241936828581
12159865292b261
1374ca77843155
1433a64cdc2693
1517e3160cac61
hexc08eb21f9a9

13232444144041 has 4 divisors (see below), whose sum is σ = 13232565715072. Its totient is φ = 13232322573012.

The previous prime is 13232444144033. The next prime is 13232444144081. The reversal of 13232444144041 is 14044144423231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13232444144041 - 23 = 13232444144033 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13232444144081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60622101 + ... + 60839986.

It is an arithmetic number, because the mean of its divisors is an integer number (3308141428768).

Almost surely, 213232444144041 is an apocalyptic number.

It is an amenable number.

13232444144041 is a deficient number, since it is larger than the sum of its proper divisors (121571031).

13232444144041 is a wasteful number, since it uses less digits than its factorization.

13232444144041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 121571030.

The product of its (nonzero) digits is 147456, while the sum is 37.

Adding to 13232444144041 its reverse (14044144423231), we get a palindrome (27276588567272).

The spelling of 13232444144041 in words is "thirteen trillion, two hundred thirty-two billion, four hundred forty-four million, one hundred forty-four thousand, forty-one".

Divisors: 1 108943 121462087 13232444144041