Base | Representation |
---|---|
bin | 1100000010010000110011… |
… | …1000010010111011011011 |
3 | 1201212001201020112101012111 |
4 | 3000210030320102323123 |
5 | 3213302201120320123 |
6 | 44051054440253151 |
7 | 2534024221563541 |
oct | 300441470227333 |
9 | 51761636471174 |
10 | 13233010323163 |
11 | 42420a7386304 |
12 | 15987904711b7 |
13 | 74cb37c29897 |
14 | 33a6a4283d91 |
15 | 17e34ab6790d |
hex | c090ce12edb |
13233010323163 has 2 divisors, whose sum is σ = 13233010323164. Its totient is φ = 13233010323162.
The previous prime is 13233010323119. The next prime is 13233010323277. The reversal of 13233010323163 is 36132301033231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13233010323163 - 225 = 13232976768731 is a prime.
It is a super-3 number, since 3×132330103231633 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (13233010353163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6616505161581 + 6616505161582.
It is an arithmetic number, because the mean of its divisors is an integer number (6616505161582).
Almost surely, 213233010323163 is an apocalyptic number.
13233010323163 is a deficient number, since it is larger than the sum of its proper divisors (1).
13233010323163 is an equidigital number, since it uses as much as digits as its factorization.
13233010323163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17496, while the sum is 31.
Adding to 13233010323163 its reverse (36132301033231), we get a palindrome (49365311356394).
The spelling of 13233010323163 in words is "thirteen trillion, two hundred thirty-three billion, ten million, three hundred twenty-three thousand, one hundred sixty-three".
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