Base | Representation |
---|---|
bin | 10011010000011011011… |
… | …100110000100101101011 |
3 | 11200111200210002001121002 |
4 | 103100123130300211223 |
5 | 133140114433413201 |
6 | 2451530451305215 |
7 | 164414603146151 |
oct | 23203334604553 |
9 | 4614623061532 |
10 | 1323310451051 |
11 | 470238284076 |
12 | 194571bab20b |
13 | 97a315a3344 |
14 | 480973ab3d1 |
15 | 2465060a76b |
hex | 1341b73096b |
1323310451051 has 4 divisors (see below), whose sum is σ = 1335677838552. Its totient is φ = 1310943063552.
The previous prime is 1323310451033. The next prime is 1323310451077. The reversal of 1323310451051 is 1501540133231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1323310451051 - 222 = 1323306256747 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1323310450051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6183693590 + ... + 6183693803.
It is an arithmetic number, because the mean of its divisors is an integer number (333919459638).
Almost surely, 21323310451051 is an apocalyptic number.
1323310451051 is a deficient number, since it is larger than the sum of its proper divisors (12367387501).
1323310451051 is a wasteful number, since it uses less digits than its factorization.
1323310451051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12367387500.
The product of its (nonzero) digits is 5400, while the sum is 29.
Adding to 1323310451051 its reverse (1501540133231), we get a palindrome (2824850584282).
The spelling of 1323310451051 in words is "one trillion, three hundred twenty-three billion, three hundred ten million, four hundred fifty-one thousand, fifty-one".
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