Base | Representation |
---|---|
bin | 10011010000011011100… |
… | …000000011000100110010 |
3 | 11200111200211200212020121 |
4 | 103100123200003010302 |
5 | 133140120144010302 |
6 | 2451530522000454 |
7 | 164414613366544 |
oct | 23203340030462 |
9 | 4614624625217 |
10 | 1323311313202 |
11 | 47023881289a |
12 | 19457234612a |
13 | 97a318158a8 |
14 | 48097553694 |
15 | 2465072ae37 |
hex | 1341b803132 |
1323311313202 has 4 divisors (see below), whose sum is σ = 1984966969806. Its totient is φ = 661655656600.
The previous prime is 1323311313161. The next prime is 1323311313217. The reversal of 1323311313202 is 2023131133231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1206484756801 + 116826556401 = 1098401^2 + 341799^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 330827828299 + ... + 330827828302.
Almost surely, 21323311313202 is an apocalyptic number.
1323311313202 is a deficient number, since it is larger than the sum of its proper divisors (661655656604).
1323311313202 is an equidigital number, since it uses as much as digits as its factorization.
1323311313202 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 661655656603.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 1323311313202 its reverse (2023131133231), we get a palindrome (3346442446433).
The spelling of 1323311313202 in words is "one trillion, three hundred twenty-three billion, three hundred eleven million, three hundred thirteen thousand, two hundred two".
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