13233120212041 has 4 divisors (see below), whose sum is σ = 13233128125392. Its totient is φ = 13233112298692.

The previous prime is 13233120212009. The next prime is 13233120212047. The reversal of 13233120212041 is 14021202133231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13233120212041 - 2⁵ = 13233120212009 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13233120211997 and 13233120212015.

It is not an unprimeable number, because it can be changed into a prime (13233120212047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 356155 + ... + 5156848.

It is an arithmetic number, because the mean of its divisors is an integer number (3308282031348).

Almost surely, 2^{13233120212041} is an apocalyptic number.

It is an amenable number.

13233120212041 is a deficient number, since it is larger than the sum of its proper divisors (7913351).

13233120212041 is an equidigital number, since it uses as much as digits as its factorization.

13233120212041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7913350.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13233120212041 its reverse (14021202133231), we get a palindrome (27254322345272).

The spelling of 13233120212041 in words is "thirteen trillion, two hundred thirty-three billion, one hundred twenty million, two hundred twelve thousand, forty-one".