Base | Representation |
---|---|
bin | 10011010000011100110… |
… | …000001000000011100001 |
3 | 11200111202022012100202002 |
4 | 103100130300020003201 |
5 | 133140141032230441 |
6 | 2451532551533345 |
7 | 164415256666511 |
oct | 23203460100341 |
9 | 4614668170662 |
10 | 1323332305121 |
11 | 470249650392 |
12 | 19457938a255 |
13 | 97a35c85648 |
14 | 4809a259841 |
15 | 246524c5b9b |
hex | 1341cc080e1 |
1323332305121 has 2 divisors, whose sum is σ = 1323332305122. Its totient is φ = 1323332305120.
The previous prime is 1323332305111. The next prime is 1323332305157. The reversal of 1323332305121 is 1215032333231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 791096398096 + 532235907025 = 889436^2 + 729545^2 .
It is a cyclic number.
It is not a de Polignac number, because 1323332305121 - 222 = 1323328110817 is a prime.
It is not a weakly prime, because it can be changed into another prime (1323332305111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661666152560 + 661666152561.
It is an arithmetic number, because the mean of its divisors is an integer number (661666152561).
Almost surely, 21323332305121 is an apocalyptic number.
It is an amenable number.
1323332305121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1323332305121 is an equidigital number, since it uses as much as digits as its factorization.
1323332305121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 29.
Adding to 1323332305121 its reverse (1215032333231), we get a palindrome (2538364638352).
The spelling of 1323332305121 in words is "one trillion, three hundred twenty-three billion, three hundred thirty-two million, three hundred five thousand, one hundred twenty-one".
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