Base | Representation |
---|---|
bin | 11110000101110011010001… |
… | …010000111011011010011001 |
3 | 122100120120210011010111110011 |
4 | 132011303101100323122121 |
5 | 114321224402024401103 |
6 | 1145244102044521521 |
7 | 36606152432550025 |
oct | 3605632120733231 |
9 | 570516704114404 |
10 | 132340043200153 |
11 | 3919310831a258 |
12 | 12a144788502a1 |
13 | 58ac7c6944a19 |
14 | 2497413da5385 |
15 | 1047705401d6d |
hex | 785cd143b699 |
132340043200153 has 16 divisors (see below), whose sum is σ = 141601799664000. Its totient is φ = 123324274517760.
The previous prime is 132340043200087. The next prime is 132340043200193. The reversal of 132340043200153 is 351002340043231.
It is a happy number.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132340043200153 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132340043200193) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 226634368 + ... + 227217553.
It is an arithmetic number, because the mean of its divisors is an integer number (8850112479000).
Almost surely, 2132340043200153 is an apocalyptic number.
It is an amenable number.
132340043200153 is a deficient number, since it is larger than the sum of its proper divisors (9261756463847).
132340043200153 is a wasteful number, since it uses less digits than its factorization.
132340043200153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 453852192.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 132340043200153 its reverse (351002340043231), we get a palindrome (483342383243384).
The spelling of 132340043200153 in words is "one hundred thirty-two trillion, three hundred forty billion, forty-three million, two hundred thousand, one hundred fifty-three".
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