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132340403113132 = 2233085100778283
BaseRepresentation
bin11110000101110011100110…
…101101111000110010101100
3122100120121201020100222020111
4132011303212231320302230
5114321231121144110012
61145244201503025404
736606164363012014
oct3605634655706254
9570517636328214
10132340403113132
11391932824a51a5
1212a1455929b264
1358ac85338bc96
142497449ad2c44
151047726ce7ba7
hex785ce6b78cac

132340403113132 has 6 divisors (see below), whose sum is σ = 231595705447988. Its totient is φ = 66170201556564.

The previous prime is 132340403113129. The next prime is 132340403113183. The reversal of 132340403113132 is 231311304043231.

132340403113132 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×1323404031131322 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132340403113094 and 132340403113103.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16542550389138 + ... + 16542550389145.

Almost surely, 2132340403113132 is an apocalyptic number.

It is an amenable number.

132340403113132 is a deficient number, since it is larger than the sum of its proper divisors (99255302334856).

132340403113132 is a wasteful number, since it uses less digits than its factorization.

132340403113132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33085100778287 (or 33085100778285 counting only the distinct ones).

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 132340403113132 its reverse (231311304043231), we get a palindrome (363651707156363).

The spelling of 132340403113132 in words is "one hundred thirty-two trillion, three hundred forty billion, four hundred three million, one hundred thirteen thousand, one hundred thirty-two".

Divisors: 1 2 4 33085100778283 66170201556566 132340403113132