Base | Representation |
---|---|
bin | 1100000010010111001111… |
… | …0101111001001101000011 |
3 | 1201212020011121222120220001 |
4 | 3000211303311321031003 |
5 | 3213314220330344010 |
6 | 44051542105100431 |
7 | 2534115065464120 |
oct | 300456365711503 |
9 | 51766147876801 |
10 | 13234737746755 |
11 | 424290347a208 |
12 | 1598b92a87717 |
13 | 750051a88515 |
14 | 33a7c9867747 |
15 | 17e3ec636c3a |
hex | c0973d79343 |
13234737746755 has 16 divisors (see below), whose sum is σ = 18175259450304. Its totient is φ = 9062867756160.
The previous prime is 13234737746677. The next prime is 13234737746779. The reversal of 13234737746755 is 55764773743231.
13234737746755 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a de Polignac number, because none of the positive numbers 2k-13234737746755 is a prime.
It is a super-2 number, since 2×132347377467552 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 257911156 + ... + 257962465.
It is an arithmetic number, because the mean of its divisors is an integer number (1135953715644).
Almost surely, 213234737746755 is an apocalyptic number.
13234737746755 is a deficient number, since it is larger than the sum of its proper divisors (4940521703549).
13234737746755 is an equidigital number, since it uses as much as digits as its factorization.
13234737746755 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 515874366.
The product of its digits is 311169600, while the sum is 64.
The spelling of 13234737746755 in words is "thirteen trillion, two hundred thirty-four billion, seven hundred thirty-seven million, seven hundred forty-six thousand, seven hundred fifty-five".
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