Base | Representation |
---|---|
bin | 11110000101111101100001… |
… | …010100100111110011010001 |
3 | 122100121122012020101222122011 |
4 | 132011331201110213303101 |
5 | 114321414422301201342 |
6 | 1145253122155142521 |
7 | 36610022254154644 |
oct | 3605754124476321 |
9 | 570548166358564 |
10 | 132351050022097 |
11 | 39197846397515 |
12 | 12a1662aa44a41 |
13 | 58b085c0ba50a |
14 | 2497b79b2da5b |
15 | 1047b4b88c717 |
hex | 785f61527cd1 |
132351050022097 has 2 divisors, whose sum is σ = 132351050022098. Its totient is φ = 132351050022096.
The previous prime is 132351050022071. The next prime is 132351050022157. The reversal of 132351050022097 is 790220050153231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 130921217610561 + 1429832411536 = 11442081^2 + 1195756^2 .
It is a cyclic number.
It is not a de Polignac number, because 132351050022097 - 27 = 132351050021969 is a prime.
It is not a weakly prime, because it can be changed into another prime (132351050022397) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66175525011048 + 66175525011049.
It is an arithmetic number, because the mean of its divisors is an integer number (66175525011049).
Almost surely, 2132351050022097 is an apocalyptic number.
It is an amenable number.
132351050022097 is a deficient number, since it is larger than the sum of its proper divisors (1).
132351050022097 is an equidigital number, since it uses as much as digits as its factorization.
132351050022097 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 113400, while the sum is 40.
The spelling of 132351050022097 in words is "one hundred thirty-two trillion, three hundred fifty-one billion, fifty million, twenty-two thousand, ninety-seven".
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