Base | Representation |
---|---|
bin | 11110000110001010110101… |
… | …010101111000111110110011 |
3 | 122100200000002110001212110001 |
4 | 132012022311111320332303 |
5 | 114322133211200331033 |
6 | 1145303444432250431 |
7 | 36611036426451652 |
oct | 3606126525707663 |
9 | 570600073055401 |
10 | 132365344542643 |
11 | 391a2911267363 |
12 | 12a1935a0a0a17 |
13 | 58b1cc97290b4 |
14 | 2498734391199 |
15 | 10481d679ae7d |
hex | 7862b5578fb3 |
132365344542643 has 4 divisors (see below), whose sum is σ = 134608824958680. Its totient is φ = 130121864126608.
The previous prime is 132365344542619. The next prime is 132365344542671. The reversal of 132365344542643 is 346245443563231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132365344542643 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132365344542043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1121740207930 + ... + 1121740208047.
It is an arithmetic number, because the mean of its divisors is an integer number (33652206239670).
Almost surely, 2132365344542643 is an apocalyptic number.
132365344542643 is a deficient number, since it is larger than the sum of its proper divisors (2243480416037).
132365344542643 is an equidigital number, since it uses as much as digits as its factorization.
132365344542643 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2243480416036.
The product of its digits is 74649600, while the sum is 55.
The spelling of 132365344542643 in words is "one hundred thirty-two trillion, three hundred sixty-five billion, three hundred forty-four million, five hundred forty-two thousand, six hundred forty-three".
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