13240000442 has 4 divisors (see below), whose sum is σ = 19860000666. Its totient is φ = 6620000220.

The previous prime is 13240000369. The next prime is 13240000447. The reversal of 13240000442 is 24400004231.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 24400004231 = 19 ⋅1284210749.

It can be written as a sum of positive squares in only one way, i.e., 12775554841 + 464445601 = 113029^2 + 21551^2 .

It is a super-3 number, since 3×13240000442³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (13240000447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3310000109 + ... + 3310000112.

Almost surely, 2^13240000442 is an apocalyptic number.

13240000442 is a deficient number, since it is larger than the sum of its proper divisors (6620000224).

13240000442 is an equidigital number, since it uses as much as digits as its factorization.

13240000442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6620000223.

The product of its (nonzero) digits is 768, while the sum is 20.

Adding to 13240000442 its reverse (24400004231), we get a palindrome (37640004673).

The spelling of 13240000442 in words is "thirteen billion, two hundred forty million, four hundred forty-two", and thus it is an aban number.