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1324000203131 = 5922440681409
BaseRepresentation
bin10011010001000100100…
…011111101000101111011
311200120110211222002120102
4103101010203331011323
5133143023023000011
62452123131150015
7164440650016154
oct23210443750573
94616424862512
101324000203131
11470561664011
12194724ba530b
1397b11465078
1448120c3892b
1524690e5673b
hex134448fd17b

1324000203131 has 4 divisors (see below), whose sum is σ = 1346440884600. Its totient is φ = 1301559521664.

The previous prime is 1324000203107. The next prime is 1324000203137. The reversal of 1324000203131 is 1313020004231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1324000203131 is a prime.

It is a super-2 number, since 2×13240002031312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1324000203137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11220340646 + ... + 11220340763.

It is an arithmetic number, because the mean of its divisors is an integer number (336610221150).

Almost surely, 21324000203131 is an apocalyptic number.

1324000203131 is a deficient number, since it is larger than the sum of its proper divisors (22440681469).

1324000203131 is an equidigital number, since it uses as much as digits as its factorization.

1324000203131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22440681468.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 1324000203131 its reverse (1313020004231), we get a palindrome (2637020207362).

The spelling of 1324000203131 in words is "one trillion, three hundred twenty-four billion, two hundred three thousand, one hundred thirty-one".

Divisors: 1 59 22440681409 1324000203131