Base | Representation |
---|---|
bin | 11110000110101011100001… |
… | …010000010101111100010001 |
3 | 122100210100200101021212022001 |
4 | 132012223201100111330101 |
5 | 114323222100400234043 |
6 | 1145331531203514001 |
7 | 36613421232564562 |
oct | 3606534120257421 |
9 | 570710611255261 |
10 | 132400441024273 |
11 | 39206791316484 |
12 | 12a24113988901 |
13 | 58b5400930ca6 |
14 | 249a303614169 |
15 | 104908ca3874d |
hex | 786ae1415f11 |
132400441024273 has 2 divisors, whose sum is σ = 132400441024274. Its totient is φ = 132400441024272.
The previous prime is 132400441024249. The next prime is 132400441024283. The reversal of 132400441024273 is 372420144004231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 75173894002944 + 57226547021329 = 8670288^2 + 7564823^2 .
It is a cyclic number.
It is not a de Polignac number, because 132400441024273 - 245 = 97216068935441 is a prime.
It is not a weakly prime, because it can be changed into another prime (132400441024283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66200220512136 + 66200220512137.
It is an arithmetic number, because the mean of its divisors is an integer number (66200220512137).
Almost surely, 2132400441024273 is an apocalyptic number.
It is an amenable number.
132400441024273 is a deficient number, since it is larger than the sum of its proper divisors (1).
132400441024273 is an equidigital number, since it uses as much as digits as its factorization.
132400441024273 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129024, while the sum is 37.
The spelling of 132400441024273 in words is "one hundred thirty-two trillion, four hundred billion, four hundred forty-one million, twenty-four thousand, two hundred seventy-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •