Base | Representation |
---|---|
bin | 11110000110101011100001… |
… | …010000010101111110010011 |
3 | 122100210100200101021212110212 |
4 | 132012223201100111332103 |
5 | 114323222100400240103 |
6 | 1145331531203514335 |
7 | 36613421232565136 |
oct | 3606534120257623 |
9 | 570710611255425 |
10 | 132400441024403 |
11 | 39206791316592 |
12 | 12a241139889ab |
13 | 58b5400931076 |
14 | 249a30361421d |
15 | 104908ca387d8 |
hex | 786ae1415f93 |
132400441024403 has 2 divisors, whose sum is σ = 132400441024404. Its totient is φ = 132400441024402.
The previous prime is 132400441024339. The next prime is 132400441024429. The reversal of 132400441024403 is 304420144004231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132400441024403 - 26 = 132400441024339 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 132400441024403.
It is not a weakly prime, because it can be changed into another prime (132400441024463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66200220512201 + 66200220512202.
It is an arithmetic number, because the mean of its divisors is an integer number (66200220512202).
Almost surely, 2132400441024403 is an apocalyptic number.
132400441024403 is a deficient number, since it is larger than the sum of its proper divisors (1).
132400441024403 is an equidigital number, since it uses as much as digits as its factorization.
132400441024403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36864, while the sum is 32.
Adding to 132400441024403 its reverse (304420144004231), we get a palindrome (436820585028634).
The spelling of 132400441024403 in words is "one hundred thirty-two trillion, four hundred billion, four hundred forty-one million, twenty-four thousand, four hundred three".
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