Base | Representation |
---|---|
bin | 1100000010101100011101… |
… | …0100010110010101110011 |
3 | 1201212202212112222221001212 |
4 | 3000223013110112111303 |
5 | 3213412401400103033 |
6 | 44054323202350335 |
7 | 2534406164213336 |
oct | 300530724262563 |
9 | 51782775887055 |
10 | 13240433206643 |
11 | 4245266405555 |
12 | 159a10235b3ab |
13 | 75074ba26b26 |
14 | 33abaa04061d |
15 | 17e632665748 |
hex | c0ac7516573 |
13240433206643 has 4 divisors (see below), whose sum is σ = 13247289983928. Its totient is φ = 13233576429360.
The previous prime is 13240433206597. The next prime is 13240433206661. The reversal of 13240433206643 is 34660233404231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13240433206643 - 216 = 13240433141107 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13240433206643.
It is not an unprimeable number, because it can be changed into a prime (13240433806643) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3428385746 + ... + 3428389607.
It is an arithmetic number, because the mean of its divisors is an integer number (3311822495982).
Almost surely, 213240433206643 is an apocalyptic number.
13240433206643 is a deficient number, since it is larger than the sum of its proper divisors (6856777285).
13240433206643 is an equidigital number, since it uses as much as digits as its factorization.
13240433206643 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6856777284.
The product of its (nonzero) digits is 746496, while the sum is 41.
The spelling of 13240433206643 in words is "thirteen trillion, two hundred forty billion, four hundred thirty-three million, two hundred six thousand, six hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •