132411131150251 has 4 divisors (see below), whose sum is σ = 132457412569104. Its totient is φ = 132364849731400.

The previous prime is 132411131150219. The next prime is 132411131150299. The reversal of 132411131150251 is 152051131114231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132411131150251 - 2⁵ = 132411131150219 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132411135150251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23140705135 + ... + 23140710856.

It is an arithmetic number, because the mean of its divisors is an integer number (33114353142276).

Almost surely, 2^{132411131150251} is an apocalyptic number.

132411131150251 is a deficient number, since it is larger than the sum of its proper divisors (46281418853).

132411131150251 is an equidigital number, since it uses as much as digits as its factorization.

132411131150251 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 46281418852.

The product of its (nonzero) digits is 3600, while the sum is 31.

Adding to 132411131150251 its reverse (152051131114231), we get a palindrome (284462262264482).

The spelling of 132411131150251 in words is "one hundred thirty-two trillion, four hundred eleven billion, one hundred thirty-one million, one hundred fifty thousand, two hundred fifty-one".