Base | Representation |
---|---|
bin | 111101101010001010… |
… | …0101011110100110001 |
3 | 110122202222001110101001 |
4 | 1323110110223310301 |
5 | 4132134232223212 |
6 | 140455011442001 |
7 | 12365162503126 |
oct | 1732424536461 |
9 | 418688043331 |
10 | 132411211057 |
11 | 51178749744 |
12 | 217b42b6301 |
13 | c6425b7338 |
14 | 65a180674d |
15 | 369e8a1657 |
hex | 1ed452bd31 |
132411211057 has 2 divisors, whose sum is σ = 132411211058. Its totient is φ = 132411211056.
The previous prime is 132411211021. The next prime is 132411211067. The reversal of 132411211057 is 750112114231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 130443046561 + 1968164496 = 361169^2 + 44364^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132411211057 is a prime.
It is not a weakly prime, because it can be changed into another prime (132411211067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66205605528 + 66205605529.
It is an arithmetic number, because the mean of its divisors is an integer number (66205605529).
Almost surely, 2132411211057 is an apocalyptic number.
It is an amenable number.
132411211057 is a deficient number, since it is larger than the sum of its proper divisors (1).
132411211057 is an equidigital number, since it uses as much as digits as its factorization.
132411211057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1680, while the sum is 28.
Adding to 132411211057 its reverse (750112114231), we get a palindrome (882523325288).
The spelling of 132411211057 in words is "one hundred thirty-two billion, four hundred eleven million, two hundred eleven thousand, fifty-seven".
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