Base | Representation |
---|---|
bin | 111101101010001010… |
… | …0101111000000110001 |
3 | 110122202222002010021121 |
4 | 1323110110233000301 |
5 | 4132134233132423 |
6 | 140455012022241 |
7 | 12365162556160 |
oct | 1732424570061 |
9 | 418688063247 |
10 | 132411224113 |
11 | 51178758533 |
12 | 217b4301981 |
13 | c6425c026c |
14 | 65a180b3d7 |
15 | 369e8a545d |
hex | 1ed452f031 |
132411224113 has 8 divisors (see below), whose sum is σ = 151885518080. Its totient is φ = 113076531360.
The previous prime is 132411224087. The next prime is 132411224117. The reversal of 132411224113 is 311422114231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132411224113 - 25 = 132411224081 is a prime.
It is a super-2 number, since 2×1324112241132 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132411224117) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 34898268 + ... + 34902061.
It is an arithmetic number, because the mean of its divisors is an integer number (18985689760).
Almost surely, 2132411224113 is an apocalyptic number.
It is an amenable number.
132411224113 is a deficient number, since it is larger than the sum of its proper divisors (19474293967).
132411224113 is an equidigital number, since it uses as much as digits as its factorization.
132411224113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 69800607.
The product of its digits is 1152, while the sum is 25.
Adding to 132411224113 its reverse (311422114231), we get a palindrome (443833338344).
The spelling of 132411224113 in words is "one hundred thirty-two billion, four hundred eleven million, two hundred twenty-four thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •