Search a number
-
+
132413050414553 is a prime number
BaseRepresentation
bin11110000110110111010000…
…110101010110010111011001
3122100211120020011002020221212
4132012313100311112113121
5114323423411401231203
61145341414322512505
736614345553620426
oct3606672065262731
9570746204066855
10132413050414553
1139211071a59a87
1212a26652805735
1358b66600cb57c
14249ab7c140d4d
151049579a2e1d8
hex786dd0d565d9

132413050414553 has 2 divisors, whose sum is σ = 132413050414554. Its totient is φ = 132413050414552.

The previous prime is 132413050414531. The next prime is 132413050414591. The reversal of 132413050414553 is 355414050314231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 121560591804304 + 10852458610249 = 11025452^2 + 3294307^2 .

It is a cyclic number.

It is not a de Polignac number, because 132413050414553 - 222 = 132413046220249 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 132413050414553.

It is not a weakly prime, because it can be changed into another prime (132413050414523) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66206525207276 + 66206525207277.

It is an arithmetic number, because the mean of its divisors is an integer number (66206525207277).

Almost surely, 2132413050414553 is an apocalyptic number.

It is an amenable number.

132413050414553 is a deficient number, since it is larger than the sum of its proper divisors (1).

132413050414553 is an equidigital number, since it uses as much as digits as its factorization.

132413050414553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432000, while the sum is 41.

The spelling of 132413050414553 in words is "one hundred thirty-two trillion, four hundred thirteen billion, fifty million, four hundred fourteen thousand, five hundred fifty-three".