Base | Representation |
---|---|
bin | 11000101010011111… |
… | …11101100110111011 |
3 | 1021011211001012212222 |
4 | 30111033331212323 |
5 | 204104300023211 |
6 | 10025533154255 |
7 | 646064052563 |
oct | 142517754673 |
9 | 37154035788 |
10 | 13241407931 |
11 | 568547a844 |
12 | 269662b98b |
13 | 13303c662b |
14 | 8d8849da3 |
15 | 52773a1db |
hex | 3153fd9bb |
13241407931 has 2 divisors, whose sum is σ = 13241407932. Its totient is φ = 13241407930.
The previous prime is 13241407909. The next prime is 13241407943. The reversal of 13241407931 is 13970414231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13241407931 - 26 = 13241407867 is a prime.
It is a super-2 number, since 2×132414079312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13241407891 and 13241407900.
It is not a weakly prime, because it can be changed into another prime (13241407031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6620703965 + 6620703966.
It is an arithmetic number, because the mean of its divisors is an integer number (6620703966).
Almost surely, 213241407931 is an apocalyptic number.
13241407931 is a deficient number, since it is larger than the sum of its proper divisors (1).
13241407931 is an equidigital number, since it uses as much as digits as its factorization.
13241407931 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 35.
The spelling of 13241407931 in words is "thirteen billion, two hundred forty-one million, four hundred seven thousand, nine hundred thirty-one".
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