132424131001 has 2 divisors, whose sum is σ = 132424131002. Its totient is φ = 132424131000.

The previous prime is 132424130983. The next prime is 132424131013. The reversal of 132424131001 is 100131424231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99429224976 + 32994906025 = 315324^2 + 181645^2 .

It is an emirp because it is prime and its reverse (100131424231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132424131001 - 2¹⁹ = 132423606713 is a prime.

It is not a weakly prime, because it can be changed into another prime (132424101001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66212065500 + 66212065501.

It is an arithmetic number, because the mean of its divisors is an integer number (66212065501).

Almost surely, 2^132424131001 is an apocalyptic number.

It is an amenable number.

132424131001 is a deficient number, since it is larger than the sum of its proper divisors (1).

132424131001 is an equidigital number, since it uses as much as digits as its factorization.

132424131001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 132424131001 its reverse (100131424231), we get a palindrome (232555555232).

The spelling of 132424131001 in words is "one hundred thirty-two billion, four hundred twenty-four million, one hundred thirty-one thousand, one".