Base | Representation |
---|---|
bin | 11000101010101100… |
… | …11110001001000011 |
3 | 1021011221020220020121 |
4 | 30111112132021003 |
5 | 204110214122201 |
6 | 10030033521111 |
7 | 646114416646 |
oct | 142526361103 |
9 | 37157226217 |
10 | 13243114051 |
11 | 5686435662 |
12 | 2697113197 |
13 | 133087307b |
14 | 8d8b71a5d |
15 | 5279759a1 |
hex | 31559e243 |
13243114051 has 2 divisors, whose sum is σ = 13243114052. Its totient is φ = 13243114050.
The previous prime is 13243114039. The next prime is 13243114061. The reversal of 13243114051 is 15041134231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13243114051 is a prime.
It is not a weakly prime, because it can be changed into another prime (13243114061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6621557025 + 6621557026.
It is an arithmetic number, because the mean of its divisors is an integer number (6621557026).
Almost surely, 213243114051 is an apocalyptic number.
13243114051 is a deficient number, since it is larger than the sum of its proper divisors (1).
13243114051 is an equidigital number, since it uses as much as digits as its factorization.
13243114051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 13243114051 its reverse (15041134231), we get a palindrome (28284248282).
The spelling of 13243114051 in words is "thirteen billion, two hundred forty-three million, one hundred fourteen thousand, fifty-one".
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