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132432044281 is a prime number
BaseRepresentation
bin111101101010110010…
…0001010000011111001
3110122211102020220011221
41323111210022003321
54132210100404111
6140501034152041
712365534542315
oct1732544120371
9418742226157
10132432044281
1151189488a89
12217bb282621
13c6469ccaa4
1465a44aab45
1536a1619371
hex1ed590a0f9

132432044281 has 2 divisors, whose sum is σ = 132432044282. Its totient is φ = 132432044280.

The previous prime is 132432044273. The next prime is 132432044321. The reversal of 132432044281 is 182440234231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 102054691600 + 30377352681 = 319460^2 + 174291^2 .

It is a cyclic number.

It is not a de Polignac number, because 132432044281 - 23 = 132432044273 is a prime.

It is a super-2 number, since 2×1324320442812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (132432041281) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66216022140 + 66216022141.

It is an arithmetic number, because the mean of its divisors is an integer number (66216022141).

Almost surely, 2132432044281 is an apocalyptic number.

It is an amenable number.

132432044281 is a deficient number, since it is larger than the sum of its proper divisors (1).

132432044281 is an equidigital number, since it uses as much as digits as its factorization.

132432044281 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36864, while the sum is 34.

The spelling of 132432044281 in words is "one hundred thirty-two billion, four hundred thirty-two million, forty-four thousand, two hundred eighty-one".