Base | Representation |
---|---|
bin | 11110000111010000110110… |
… | …110100010110000110101011 |
3 | 122100221012011100002101100212 |
4 | 132013100312310112012223 |
5 | 114324401201443344042 |
6 | 1145402201244051335 |
7 | 36616340553662306 |
oct | 3607206664260653 |
9 | 570835140071325 |
10 | 132440531231147 |
11 | 39221794187257 |
12 | 12a2ba41b33b4b |
13 | 58b911c5a86a9 |
14 | 249c227b83b3d |
15 | 104a1373dd482 |
hex | 787436d161ab |
132440531231147 has 2 divisors, whose sum is σ = 132440531231148. Its totient is φ = 132440531231146.
The previous prime is 132440531231117. The next prime is 132440531231191. The reversal of 132440531231147 is 741132135044231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132440531231147 - 212 = 132440531227051 is a prime.
It is not a weakly prime, because it can be changed into another prime (132440531231117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66220265615573 + 66220265615574.
It is an arithmetic number, because the mean of its divisors is an integer number (66220265615574).
Almost surely, 2132440531231147 is an apocalyptic number.
132440531231147 is a deficient number, since it is larger than the sum of its proper divisors (1).
132440531231147 is an equidigital number, since it uses as much as digits as its factorization.
132440531231147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 241920, while the sum is 41.
Adding to 132440531231147 its reverse (741132135044231), we get a palindrome (873572666275378).
The spelling of 132440531231147 in words is "one hundred thirty-two trillion, four hundred forty billion, five hundred thirty-one million, two hundred thirty-one thousand, one hundred forty-seven".
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