13244240243411 has 4 divisors (see below), whose sum is σ = 13941305519400. Its totient is φ = 12547174967424.

The previous prime is 13244240243363. The next prime is 13244240243417. The reversal of 13244240243411 is 11434204244231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13244240243411 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13244240243417) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 348532637966 + ... + 348532638003.

It is an arithmetic number, because the mean of its divisors is an integer number (3485326379850).

Almost surely, 2^{13244240243411} is an apocalyptic number.

13244240243411 is a deficient number, since it is larger than the sum of its proper divisors (697065275989).

13244240243411 is an equidigital number, since it uses as much as digits as its factorization.

13244240243411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 697065275988.

The product of its (nonzero) digits is 73728, while the sum is 35.

Adding to 13244240243411 its reverse (11434204244231), we get a palindrome (24678444487642).

The spelling of 13244240243411 in words is "thirteen trillion, two hundred forty-four billion, two hundred forty million, two hundred forty-three thousand, four hundred eleven".