Base | Representation |
---|---|
bin | 10011010001011101111… |
… | …101111001011100111001 |
3 | 11200121120112222212220021 |
4 | 103101131331321130321 |
5 | 133144411131344421 |
6 | 2452233314530441 |
7 | 164454343641622 |
oct | 23213575713471 |
9 | 4617515885807 |
10 | 1324426434361 |
11 | 470760215928 |
12 | 194823896a21 |
13 | 97b7b85c0b4 |
14 | 481616aaa49 |
15 | 246b859c341 |
hex | 1345df79739 |
1324426434361 has 2 divisors, whose sum is σ = 1324426434362. Its totient is φ = 1324426434360.
The previous prime is 1324426434337. The next prime is 1324426434407. The reversal of 1324426434361 is 1634346244231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 885752028736 + 438674405625 = 941144^2 + 662325^2 .
It is an emirp because it is prime and its reverse (1634346244231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1324426434361 - 29 = 1324426433849 is a prime.
It is not a weakly prime, because it can be changed into another prime (1324426434061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662213217180 + 662213217181.
It is an arithmetic number, because the mean of its divisors is an integer number (662213217181).
Almost surely, 21324426434361 is an apocalyptic number.
It is an amenable number.
1324426434361 is a deficient number, since it is larger than the sum of its proper divisors (1).
1324426434361 is an equidigital number, since it uses as much as digits as its factorization.
1324426434361 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 995328, while the sum is 43.
The spelling of 1324426434361 in words is "one trillion, three hundred twenty-four billion, four hundred twenty-six million, four hundred thirty-four thousand, three hundred sixty-one".
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