Base | Representation |
---|---|
bin | 111101101011001000… |
… | …0000100001100000001 |
3 | 110122212012220200022121 |
4 | 1323112100010030001 |
5 | 4132221022221221 |
6 | 140502125004241 |
7 | 12366034432063 |
oct | 1732620041401 |
9 | 418765820277 |
10 | 132443554561 |
11 | 51194a2a90a |
12 | 218030b3681 |
13 | c6491ccbc6 |
14 | 65a5c25733 |
15 | 36a263ea41 |
hex | 1ed6404301 |
132443554561 has 2 divisors, whose sum is σ = 132443554562. Its totient is φ = 132443554560.
The previous prime is 132443554519. The next prime is 132443554601. The reversal of 132443554561 is 165455344231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 98521282161 + 33922272400 = 313881^2 + 184180^2 .
It is a cyclic number.
It is not a de Polignac number, because 132443554561 - 211 = 132443552513 is a prime.
It is not a weakly prime, because it can be changed into another prime (132443554861) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66221777280 + 66221777281.
It is an arithmetic number, because the mean of its divisors is an integer number (66221777281).
Almost surely, 2132443554561 is an apocalyptic number.
It is an amenable number.
132443554561 is a deficient number, since it is larger than the sum of its proper divisors (1).
132443554561 is an equidigital number, since it uses as much as digits as its factorization.
132443554561 is an evil number, because the sum of its binary digits is even.
The product of its digits is 864000, while the sum is 43.
Adding to 132443554561 its reverse (165455344231), we get a palindrome (297898898792).
The spelling of 132443554561 in words is "one hundred thirty-two billion, four hundred forty-three million, five hundred fifty-four thousand, five hundred sixty-one".
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