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13244420216257 is a prime number
BaseRepresentation
bin1100000010111011010011…
…1101100101010111000001
31201220011011102021000001121
43000232310331211113001
53213444033033410012
644100222550032241
72534610036224146
oct300566475452701
951804142230047
1013244420216257
114246a21a2691a
12159aa35648681
13750c35a4a809
1433b0677723cd
1517e7b76c1a07
hexc0bb4f655c1

13244420216257 has 2 divisors, whose sum is σ = 13244420216258. Its totient is φ = 13244420216256.

The previous prime is 13244420216213. The next prime is 13244420216299. The reversal of 13244420216257 is 75261202444231.

13244420216257 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11557341352881 + 1687078863376 = 3399609^2 + 1298876^2 .

It is a cyclic number.

It is not a de Polignac number, because 13244420216257 - 231 = 13242272732609 is a prime.

It is not a weakly prime, because it can be changed into another prime (13244420216557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6622210108128 + 6622210108129.

It is an arithmetic number, because the mean of its divisors is an integer number (6622210108129).

Almost surely, 213244420216257 is an apocalyptic number.

It is an amenable number.

13244420216257 is a deficient number, since it is larger than the sum of its proper divisors (1).

13244420216257 is an equidigital number, since it uses as much as digits as its factorization.

13244420216257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 645120, while the sum is 43.

The spelling of 13244420216257 in words is "thirteen trillion, two hundred forty-four billion, four hundred twenty million, two hundred sixteen thousand, two hundred fifty-seven".