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1324443434131 = 8795915057509
BaseRepresentation
bin10011010001011110111…
…110101111110010010011
311200121121201222120012101
4103101132332233302103
5133144430004343011
62452235123141231
7164454641303626
oct23213676576223
94617551876171
101324443434131
11470769877024
12194829514817
1397b82231a2c
1448163a53dbd
15246b9d092c1
hex1345efafc93

1324443434131 has 4 divisors (see below), whose sum is σ = 1324458579600. Its totient is φ = 1324428288664.

The previous prime is 1324443434101. The next prime is 1324443434143. The reversal of 1324443434131 is 1314343444231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1324443434131 - 27 = 1324443434003 is a prime.

It is a super-2 number, since 2×13244434341312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1324443434101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7440796 + ... + 7616713.

It is an arithmetic number, because the mean of its divisors is an integer number (331114644900).

Almost surely, 21324443434131 is an apocalyptic number.

1324443434131 is a deficient number, since it is larger than the sum of its proper divisors (15145469).

1324443434131 is an equidigital number, since it uses as much as digits as its factorization.

1324443434131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15145468.

The product of its digits is 165888, while the sum is 37.

Adding to 1324443434131 its reverse (1314343444231), we get a palindrome (2638786878362).

The spelling of 1324443434131 in words is "one trillion, three hundred twenty-four billion, four hundred forty-three million, four hundred thirty-four thousand, one hundred thirty-one".

Divisors: 1 87959 15057509 1324443434131