Base | Representation |
---|---|
bin | 11110000111011110011000… |
… | …100101001100110110110011 |
3 | 122100222120122121121212101002 |
4 | 132013132120211030312303 |
5 | 114330120423410031123 |
6 | 1145413002435232215 |
7 | 36620363526201620 |
oct | 3607363045146663 |
9 | 570876577555332 |
10 | 132455056330163 |
11 | 39227968225116 |
12 | 12a3281644866b |
13 | 58ba5c5919938 |
14 | 249cc04ca7347 |
15 | 104a6d7696528 |
hex | 78779894cdb3 |
132455056330163 has 4 divisors (see below), whose sum is σ = 151377207234480. Its totient is φ = 113532905425848.
The previous prime is 132455056330153. The next prime is 132455056330169. The reversal of 132455056330163 is 361033650554231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132455056330163 - 240 = 131355544702387 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132455056330169) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9461075452148 + ... + 9461075452161.
It is an arithmetic number, because the mean of its divisors is an integer number (37844301808620).
Almost surely, 2132455056330163 is an apocalyptic number.
132455056330163 is a deficient number, since it is larger than the sum of its proper divisors (18922150904317).
132455056330163 is an equidigital number, since it uses as much as digits as its factorization.
132455056330163 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18922150904316.
The product of its (nonzero) digits is 2916000, while the sum is 47.
The spelling of 132455056330163 in words is "one hundred thirty-two trillion, four hundred fifty-five billion, fifty-six million, three hundred thirty thousand, one hundred sixty-three".
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