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132455306600753 is a prime number
BaseRepresentation
bin11110000111011110100111…
…011111111010000100110001
3122100222121022001112221002012
4132013132213133322010301
5114330121431442211003
61145413043335332305
736620402655361523
oct3607364737720461
9570877261487065
10132455306600753
1139227a86523114
1212a32886221095
1358ba635725546
14249cc2a213a13
15104a6ee6308d8
hex7877a77fa131

132455306600753 has 2 divisors, whose sum is σ = 132455306600754. Its totient is φ = 132455306600752.

The previous prime is 132455306600717. The next prime is 132455306600767. The reversal of 132455306600753 is 357006603554231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126840572571904 + 5614734028849 = 11262352^2 + 2369543^2 .

It is a cyclic number.

It is not a de Polignac number, because 132455306600753 - 226 = 132455239491889 is a prime.

It is a super-3 number, since 3×1324553066007533 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (132455306600453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66227653300376 + 66227653300377.

It is an arithmetic number, because the mean of its divisors is an integer number (66227653300377).

Almost surely, 2132455306600753 is an apocalyptic number.

It is an amenable number.

132455306600753 is a deficient number, since it is larger than the sum of its proper divisors (1).

132455306600753 is an equidigital number, since it uses as much as digits as its factorization.

132455306600753 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6804000, while the sum is 50.

The spelling of 132455306600753 in words is "one hundred thirty-two trillion, four hundred fifty-five billion, three hundred six million, six hundred thousand, seven hundred fifty-three".