Base | Representation |
---|---|
bin | 11000101011010010… |
… | …10111101111110001 |
3 | 1021012021120121121011 |
4 | 30111221113233301 |
5 | 204113001143333 |
6 | 10030332030521 |
7 | 646204503454 |
oct | 142551275761 |
9 | 37167517534 |
10 | 13248068593 |
11 | 568920a021 |
12 | 2698902441 |
13 | 13318b9256 |
14 | 8d96a149b |
15 | 5281039cd |
hex | 315a57bf1 |
13248068593 has 2 divisors, whose sum is σ = 13248068594. Its totient is φ = 13248068592.
The previous prime is 13248068551. The next prime is 13248068597. The reversal of 13248068593 is 39586084231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12694078224 + 553990369 = 112668^2 + 23537^2 .
It is a cyclic number.
It is not a de Polignac number, because 13248068593 - 233 = 4658134001 is a prime.
It is a super-2 number, since 2×132480685932 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13248068597) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6624034296 + 6624034297.
It is an arithmetic number, because the mean of its divisors is an integer number (6624034297).
Almost surely, 213248068593 is an apocalyptic number.
It is an amenable number.
13248068593 is a deficient number, since it is larger than the sum of its proper divisors (1).
13248068593 is an equidigital number, since it uses as much as digits as its factorization.
13248068593 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1244160, while the sum is 49.
The spelling of 13248068593 in words is "thirteen billion, two hundred forty-eight million, sixty-eight thousand, five hundred ninety-three".
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