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132491041481 is a prime number
BaseRepresentation
bin111101101100100010…
…1001101101011001001
3110122222112021021010102
41323121011031223021
54132320201311411
6140510542455145
712400152161651
oct1733105155311
9418875237112
10132491041481
11512098144a7
1221816b944b5
13c655cb8486
1465ac267361
1536a68bed3b
hex1ed914dac9

132491041481 has 2 divisors, whose sum is σ = 132491041482. Its totient is φ = 132491041480.

The previous prime is 132491041457. The next prime is 132491041511. The reversal of 132491041481 is 184140194231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 119508490000 + 12982551481 = 345700^2 + 113941^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132491041481 is a prime.

It is a super-2 number, since 2×1324910414812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (132491041411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66245520740 + 66245520741.

It is an arithmetic number, because the mean of its divisors is an integer number (66245520741).

Almost surely, 2132491041481 is an apocalyptic number.

It is an amenable number.

132491041481 is a deficient number, since it is larger than the sum of its proper divisors (1).

132491041481 is an equidigital number, since it uses as much as digits as its factorization.

132491041481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27648, while the sum is 38.

The spelling of 132491041481 in words is "one hundred thirty-two billion, four hundred ninety-one million, forty-one thousand, four hundred eighty-one".