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13250113 = 31427423
BaseRepresentation
bin110010100010…
…111001000001
3220221011201221
4302202321001
511343000423
61151555041
7220424032
oct62427101
926834657
1013250113
117530008
12452ba81
13298c006
141a8ca89
15126ae5d
hexca2e41

13250113 has 4 divisors (see below), whose sum is σ = 13677568. Its totient is φ = 12822660.

The previous prime is 13250101. The next prime is 13250137. The reversal of 13250113 is 31105231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31105231 = 193161167.

It is a cyclic number.

It is not a de Polignac number, because 13250113 - 221 = 11152961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13250143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 213681 + ... + 213742.

It is an arithmetic number, because the mean of its divisors is an integer number (3419392).

Almost surely, 213250113 is an apocalyptic number.

It is an amenable number.

13250113 is a deficient number, since it is larger than the sum of its proper divisors (427455).

13250113 is an equidigital number, since it uses as much as digits as its factorization.

13250113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 427454.

The product of its (nonzero) digits is 90, while the sum is 16.

The square root of 13250113 is about 3640.0704663509. The cubic root of 13250113 is about 236.6318472436.

Adding to 13250113 its reverse (31105231), we get a palindrome (44355344).

The spelling of 13250113 in words is "thirteen million, two hundred fifty thousand, one hundred thirteen".

Divisors: 1 31 427423 13250113