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132504564236531 is a prime number
BaseRepresentation
bin11110001000001100011111…
…011110111000000011110011
3122101011022102220111002102212
4132020030133132320003303
5114331423321421032111
61145451431221402335
736624065424360224
oct3610143736700363
9571138386432385
10132504564236531
1139246963140a13
1212a403325693ab
1358c21857421a6
1424a13800dd24b
15104bb33c3598b
hex78831f7b80f3

132504564236531 has 2 divisors, whose sum is σ = 132504564236532. Its totient is φ = 132504564236530.

The previous prime is 132504564236497. The next prime is 132504564236567. The reversal of 132504564236531 is 135632465405231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 132504564236531 - 26 = 132504564236467 is a prime.

It is a super-2 number, since 2×1325045642365312 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 132504564236531.

It is not a weakly prime, because it can be changed into another prime (132504564238531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66252282118265 + 66252282118266.

It is an arithmetic number, because the mean of its divisors is an integer number (66252282118266).

Almost surely, 2132504564236531 is an apocalyptic number.

132504564236531 is a deficient number, since it is larger than the sum of its proper divisors (1).

132504564236531 is an equidigital number, since it uses as much as digits as its factorization.

132504564236531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776000, while the sum is 50.

The spelling of 132504564236531 in words is "one hundred thirty-two trillion, five hundred four billion, five hundred sixty-four million, two hundred thirty-six thousand, five hundred thirty-one".