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13251145541033 is a prime number
BaseRepresentation
bin1100000011010100010111…
…0100101010010110101001
31201220210112010010220021102
43000311011310222112221
53214101321224303113
644103254153051145
72535235511441051
oct300650564522651
951823463126242
1013251145541033
114249863223974
1215a01b19b6ab5
1375176818192a
1433b504a2c561
1517ea5cd30758
hexc0d45d2a5a9

13251145541033 has 2 divisors, whose sum is σ = 13251145541034. Its totient is φ = 13251145541032.

The previous prime is 13251145541027. The next prime is 13251145541063. The reversal of 13251145541033 is 33014554115231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12849737130409 + 401408410624 = 3584653^2 + 633568^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13251145541033 is a prime.

It is not a weakly prime, because it can be changed into another prime (13251145541063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6625572770516 + 6625572770517.

It is an arithmetic number, because the mean of its divisors is an integer number (6625572770517).

Almost surely, 213251145541033 is an apocalyptic number.

It is an amenable number.

13251145541033 is a deficient number, since it is larger than the sum of its proper divisors (1).

13251145541033 is an equidigital number, since it uses as much as digits as its factorization.

13251145541033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108000, while the sum is 38.

Adding to 13251145541033 its reverse (33014554115231), we get a palindrome (46265699656264).

The spelling of 13251145541033 in words is "thirteen trillion, two hundred fifty-one billion, one hundred forty-five million, five hundred forty-one thousand, thirty-three".