Base | Representation |
---|---|
bin | 1100000011010100010111… |
… | …0100101010010110101001 |
3 | 1201220210112010010220021102 |
4 | 3000311011310222112221 |
5 | 3214101321224303113 |
6 | 44103254153051145 |
7 | 2535235511441051 |
oct | 300650564522651 |
9 | 51823463126242 |
10 | 13251145541033 |
11 | 4249863223974 |
12 | 15a01b19b6ab5 |
13 | 75176818192a |
14 | 33b504a2c561 |
15 | 17ea5cd30758 |
hex | c0d45d2a5a9 |
13251145541033 has 2 divisors, whose sum is σ = 13251145541034. Its totient is φ = 13251145541032.
The previous prime is 13251145541027. The next prime is 13251145541063. The reversal of 13251145541033 is 33014554115231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12849737130409 + 401408410624 = 3584653^2 + 633568^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13251145541033 is a prime.
It is not a weakly prime, because it can be changed into another prime (13251145541063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6625572770516 + 6625572770517.
It is an arithmetic number, because the mean of its divisors is an integer number (6625572770517).
Almost surely, 213251145541033 is an apocalyptic number.
It is an amenable number.
13251145541033 is a deficient number, since it is larger than the sum of its proper divisors (1).
13251145541033 is an equidigital number, since it uses as much as digits as its factorization.
13251145541033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108000, while the sum is 38.
Adding to 13251145541033 its reverse (33014554115231), we get a palindrome (46265699656264).
The spelling of 13251145541033 in words is "thirteen trillion, two hundred fifty-one billion, one hundred forty-five million, five hundred forty-one thousand, thirty-three".
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