13252531140441 has 24 divisors (see below), whose sum is σ = 20536063591680. Its totient is φ = 8530364867472.

The previous prime is 13252531140397. The next prime is 13252531140469. The reversal of 13252531140441 is 14404113525231.

13252531140441 is a `hidden beast` number, since 1 + 3 + 2 + 52 + 53 + 114 + 0 + 441 = 666.

It is not a de Polignac number, because 13252531140441 - 2¹³ = 13252531132249 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13252531140396 and 13252531140405.

It is not an unprimeable number, because it can be changed into a prime (13252531140941) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 940288905 + ... + 940302998.

It is an arithmetic number, because the mean of its divisors is an integer number (855669316320).

Almost surely, 2^{13252531140441} is an apocalyptic number.

It is an amenable number.

13252531140441 is a deficient number, since it is larger than the sum of its proper divisors (7283532451239).

13252531140441 is an equidigital number, since it uses as much as digits as its factorization.

13252531140441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1880591947 (or 1880591935 counting only the distinct ones).

The product of its (nonzero) digits is 57600, while the sum is 36.

Adding to 13252531140441 its reverse (14404113525231), we get a palindrome (27656644665672).

The spelling of 13252531140441 in words is "thirteen trillion, two hundred fifty-two billion, five hundred thirty-one million, one hundred forty thousand, four hundred forty-one".