Base | Representation |
---|---|
bin | 1100000011011101010000… |
… | …1011111101101101101001 |
3 | 1201221000200120110220122202 |
4 | 3000313110023331231221 |
5 | 3214121214201424223 |
6 | 44104331154225545 |
7 | 2535351633226025 |
oct | 300672413755551 |
9 | 51830616426582 |
10 | 13253534014313 |
11 | 424a87948322a |
12 | 15a07598852b5 |
13 | 751a58c62b28 |
14 | 33b68dd2b385 |
15 | 17eb4c87b428 |
hex | c0dd42fdb69 |
13253534014313 has 2 divisors, whose sum is σ = 13253534014314. Its totient is φ = 13253534014312.
The previous prime is 13253534014297. The next prime is 13253534014321. The reversal of 13253534014313 is 31341043535231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9386698867984 + 3866835146329 = 3063772^2 + 1966427^2 .
It is a cyclic number.
It is not a de Polignac number, because 13253534014313 - 24 = 13253534014297 is a prime.
It is not a weakly prime, because it can be changed into another prime (13253534014813) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6626767007156 + 6626767007157.
It is an arithmetic number, because the mean of its divisors is an integer number (6626767007157).
Almost surely, 213253534014313 is an apocalyptic number.
It is an amenable number.
13253534014313 is a deficient number, since it is larger than the sum of its proper divisors (1).
13253534014313 is an equidigital number, since it uses as much as digits as its factorization.
13253534014313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 194400, while the sum is 38.
Adding to 13253534014313 its reverse (31341043535231), we get a palindrome (44594577549544).
The spelling of 13253534014313 in words is "thirteen trillion, two hundred fifty-three billion, five hundred thirty-four million, fourteen thousand, three hundred thirteen".
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