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13253534014313 is a prime number
BaseRepresentation
bin1100000011011101010000…
…1011111101101101101001
31201221000200120110220122202
43000313110023331231221
53214121214201424223
644104331154225545
72535351633226025
oct300672413755551
951830616426582
1013253534014313
11424a87948322a
1215a07598852b5
13751a58c62b28
1433b68dd2b385
1517eb4c87b428
hexc0dd42fdb69

13253534014313 has 2 divisors, whose sum is σ = 13253534014314. Its totient is φ = 13253534014312.

The previous prime is 13253534014297. The next prime is 13253534014321. The reversal of 13253534014313 is 31341043535231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9386698867984 + 3866835146329 = 3063772^2 + 1966427^2 .

It is a cyclic number.

It is not a de Polignac number, because 13253534014313 - 24 = 13253534014297 is a prime.

It is not a weakly prime, because it can be changed into another prime (13253534014813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6626767007156 + 6626767007157.

It is an arithmetic number, because the mean of its divisors is an integer number (6626767007157).

Almost surely, 213253534014313 is an apocalyptic number.

It is an amenable number.

13253534014313 is a deficient number, since it is larger than the sum of its proper divisors (1).

13253534014313 is an equidigital number, since it uses as much as digits as its factorization.

13253534014313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 194400, while the sum is 38.

Adding to 13253534014313 its reverse (31341043535231), we get a palindrome (44594577549544).

The spelling of 13253534014313 in words is "thirteen trillion, two hundred fifty-three billion, five hundred thirty-four million, fourteen thousand, three hundred thirteen".