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132536024041801 is a prime number
BaseRepresentation
bin11110001000101001110010…
…101000100000100101001001
3122101021022122101122210011211
4132020221302220200211021
5114332432234123314201
61145514113042253121
736626261141325142
oct3610516250404511
9571238571583154
10132536024041801
1139259237401286
1212a464523571a1
1358c512a395193
1424a2ac6386ac9
15104c875ab9651
hex788a72a20949

132536024041801 has 2 divisors, whose sum is σ = 132536024041802. Its totient is φ = 132536024041800.

The previous prime is 132536024041709. The next prime is 132536024041853. The reversal of 132536024041801 is 108140420635231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 132418528655625 + 117495386176 = 11507325^2 + 342776^2 .

It is a cyclic number.

It is not a de Polignac number, because 132536024041801 - 233 = 132527434107209 is a prime.

It is not a weakly prime, because it can be changed into another prime (132536024051801) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66268012020900 + 66268012020901.

It is an arithmetic number, because the mean of its divisors is an integer number (66268012020901).

Almost surely, 2132536024041801 is an apocalyptic number.

It is an amenable number.

132536024041801 is a deficient number, since it is larger than the sum of its proper divisors (1).

132536024041801 is an equidigital number, since it uses as much as digits as its factorization.

132536024041801 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 138240, while the sum is 40.

The spelling of 132536024041801 in words is "one hundred thirty-two trillion, five hundred thirty-six billion, twenty-four million, forty-one thousand, eight hundred one".