Base | Representation |
---|---|
bin | 10011010010011000000… |
… | …000001001101000001011 |
3 | 11200201002102010101202211 |
4 | 103102120000021220023 |
5 | 133203404411302220 |
6 | 2452514100005551 |
7 | 164520435665152 |
oct | 23223000115013 |
9 | 4621072111684 |
10 | 1325400103435 |
11 | 47110a894911 |
12 | 194a559908b7 |
13 | 97ca54aa345 |
14 | 48214b22599 |
15 | 24723ccbb5a |
hex | 13498009a0b |
1325400103435 has 16 divisors (see below), whose sum is σ = 1610090608896. Its totient is φ = 1047253539168.
The previous prime is 1325400103411. The next prime is 1325400103441. The reversal of 1325400103435 is 5343010045231.
It is a cyclic number.
It is not a de Polignac number, because 1325400103435 - 25 = 1325400103403 is a prime.
It is a super-5 number, since 5×13254001034355 (a number of 62 digits) contains 55555 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1325400103397 and 1325400103406.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1054192 + ... + 1939618.
It is an arithmetic number, because the mean of its divisors is an integer number (100630663056).
Almost surely, 21325400103435 is an apocalyptic number.
1325400103435 is a deficient number, since it is larger than the sum of its proper divisors (284690505461).
1325400103435 is an equidigital number, since it uses as much as digits as its factorization.
1325400103435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 889122.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 1325400103435 its reverse (5343010045231), we get a palindrome (6668410148666).
The spelling of 1325400103435 in words is "one trillion, three hundred twenty-five billion, four hundred million, one hundred three thousand, four hundred thirty-five".
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