Base | Representation |
---|---|
bin | 111101101110000000… |
… | …0010111110010110011 |
3 | 110200002221120220001112 |
4 | 1323130000113302303 |
5 | 4132420231310414 |
6 | 140515454223535 |
7 | 12401316202652 |
oct | 1733400276263 |
9 | 420087526045 |
10 | 132540103859 |
11 | 51234484819 |
12 | 2182b4b4bab |
13 | c663205b77 |
14 | 65b4999199 |
15 | 36aad61d3e |
hex | 1edc017cb3 |
132540103859 has 2 divisors, whose sum is σ = 132540103860. Its totient is φ = 132540103858.
The previous prime is 132540103769. The next prime is 132540103867. The reversal of 132540103859 is 958301045231.
It is a strong prime.
It is an emirp because it is prime and its reverse (958301045231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132540103859 - 212 = 132540099763 is a prime.
It is not a weakly prime, because it can be changed into another prime (132540103159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66270051929 + 66270051930.
It is an arithmetic number, because the mean of its divisors is an integer number (66270051930).
Almost surely, 2132540103859 is an apocalyptic number.
132540103859 is a deficient number, since it is larger than the sum of its proper divisors (1).
132540103859 is an equidigital number, since it uses as much as digits as its factorization.
132540103859 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129600, while the sum is 41.
The spelling of 132540103859 in words is "one hundred thirty-two billion, five hundred forty million, one hundred three thousand, eight hundred fifty-nine".
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