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13254113234 = 26627056617
BaseRepresentation
bin11000101100000000…
…11011011111010010
31021012200221201021202
430112000123133102
5204121023110414
610031105351202
7646310050355
oct142600333722
937180851252
1013254113234
11569166849a
12269a938502
131332c2466b
148da3d629c
155288e99de
hex31601b7d2

13254113234 has 4 divisors (see below), whose sum is σ = 19881169854. Its totient is φ = 6627056616.

The previous prime is 13254113207. The next prime is 13254113237. The reversal of 13254113234 is 43231145231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 9555649009 + 3698464225 = 97753^2 + 60815^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13254113197 and 13254113206.

It is not an unprimeable number, because it can be changed into a prime (13254113237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3313528307 + ... + 3313528310.

Almost surely, 213254113234 is an apocalyptic number.

13254113234 is a deficient number, since it is larger than the sum of its proper divisors (6627056620).

13254113234 is an equidigital number, since it uses as much as digits as its factorization.

13254113234 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6627056619.

The product of its digits is 8640, while the sum is 29.

Adding to 13254113234 its reverse (43231145231), we get a palindrome (56485258465).

The spelling of 13254113234 in words is "thirteen billion, two hundred fifty-four million, one hundred thirteen thousand, two hundred thirty-four".

Divisors: 1 2 6627056617 13254113234