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132545451320033 is a prime number
BaseRepresentation
bin11110001000110010100100…
…100010101110001011100001
3122101022012222101202010201212
4132020302210202232023201
5114333111041014220113
61145522312325435505
736630043563012263
oct3610624442561341
9571265871663655
10132545451320033
11392622348a9a14
1212a4824356bb95
1358c5ca0517c1b
1424a333c423b33
15104cc285470a8
hex788ca48ae2e1

132545451320033 has 2 divisors, whose sum is σ = 132545451320034. Its totient is φ = 132545451320032.

The previous prime is 132545451320011. The next prime is 132545451320047. The reversal of 132545451320033 is 330023154545231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130243033533649 + 2302417786384 = 11412407^2 + 1517372^2 .

It is a cyclic number.

It is not a de Polignac number, because 132545451320033 - 218 = 132545451057889 is a prime.

It is not a weakly prime, because it can be changed into another prime (132545451020033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66272725660016 + 66272725660017.

It is an arithmetic number, because the mean of its divisors is an integer number (66272725660017).

Almost surely, 2132545451320033 is an apocalyptic number.

It is an amenable number.

132545451320033 is a deficient number, since it is larger than the sum of its proper divisors (1).

132545451320033 is an equidigital number, since it uses as much as digits as its factorization.

132545451320033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648000, while the sum is 41.

The spelling of 132545451320033 in words is "one hundred thirty-two trillion, five hundred forty-five billion, four hundred fifty-one million, three hundred twenty thousand, thirty-three".